y^(3/2)-13y^(1/2)+40y^(-1/2)=0

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Solution for y^(3/2)-13y^(1/2)+40y^(-1/2)=0 equation: 


D( y )

y = 0

y < 0

y = 0

y = 0

y < 0

y in (0:+oo)

y^(3/2)-(13*y^(1/2))+40*y^(-1/2) = 0

y^(3/2)-13*y^(1/2)+40*y^(-1/2) = 0

y^(3/2)-13*y^(1/2)+40*y^(-1/2) = 0

y^(-1/2)*(y^2-13*y+40) = 0

y^2-13*y+40 = 0

DELTA = (-13)^2-(1*4*40)

DELTA = 9

DELTA > 0

y = (9^(1/2)+13)/(1*2) or y = (13-9^(1/2))/(1*2)

y = 8 or y = 5

1/(y^(1/2)) = 0

1*y^(-1/2) = 0 // : 1

y^(-1/2) = 0

y naleu017Cy do O

y in { 5, 8 }

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